# Convert Numbers to words Using Python

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Unlock the power of Python to convert numbers into words with ease. This project is your gateway to transforming numerical data into human-readable text, which can be useful for generating invoices, checks, or even educational applications.

Whether you’re a coding novice or an experienced programmer, our step-by-step guide will show you how to create a Python script that effortlessly converts digits into words. Join us on this journey to make numbers more accessible and expressive through the magic of Python!

``````

one_digit_words = {
'0': ["zero"],
'1': ["one"],
'2': ["two", "twen"],
'3': ["three", "thir"],
'4': ["four", "for"],
'5': ["five", "fif"],
'6': ["six"],
'7': ["seven"],
'8': ["eight"],
'9': ["nine"],
}

two_digit_words = ["ten", "eleven", "twelve"]
hundred = "hundred"
large_sum_words = ["thousand", "million", "billion", "trillion", "quadrillion", "quintillion", "sextillion", "septillion", "octillion", "nonillion"]

def converter(n):
word = []

if n.startswith('-'):
word.append("(negative)")
n = n[1:]

if len(n) % 3 != 0 and len(n) > 3:
n = n.zfill(3 * (((len(n)-1) // 3) + 1))

sum_list = [n[i:i + 3] for i in range(0, len(n), 3)]
skip = False

for i, num in enumerate(sum_list):
if num != '000': skip = False

for _ in range(len(num)):
num = num.lstrip('0')
if len(num) == 1:
if (len(sum_list) > 1 or (len(sum_list) == 1 and len(sum_list[0]) == 3)) and i == len(sum_list) - 1 and (word[-1] in large_sum_words or hundred in word[-1]):
word.append("and")
word.append(one_digit_words[num][0])
num = num[1:]
break

if len(num) == 2:
if num[0] != '0':
if (len(sum_list) > 1 or (len(sum_list) == 1 and len(sum_list[0]) == 3)) and i == len(sum_list) - 1:
word.append("and")
if num.startswith('1'):
if int(num[1]) in range(3):
word.append(two_digit_words[int(num[1])])
else:
number = one_digit_words[num[1]][1 if int(num[1]) in range(3, 6, 2) else 0]
word.append(number + ("teen" if not number[-1] == 't' else "een"))
else:
word.append(one_digit_words[num[0]][1 if int(num[0]) in range(2, 6) else 0] + ("ty " if num[0] != '8' else 'y ') + (one_digit_words[num[1]][0] if num[1] != '0' else ""))
break
else:
num = num[1:]
continue

if len(num) == 3:
if num[0] != '0':
word.append(one_digit_words[num[0]][0] + " " + hundred)
if num[1:] == '00': break
num = num[1:]

if len(sum_list[i:]) > 1 and not skip:
word.append(large_sum_words[len(sum_list[i:]) - 2])
skip = True

word = " ".join(map(str.strip, word))
return word[0].lstrip().upper() + word[1:].rstrip().lower() if "negative" not in word else word[:11].lstrip() + word[11].upper() + word[12:].rstrip().lower()

if __name__ == "__main__":
while True:
try:
n = input("Enter any number to convert it into words or 'exit' to stop: ")
if n == "exit":
break
int(n)
print(n, "-->", converter(n))
except ValueError:
print("Error: Invalid Number!")
``````
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